(9x+8)(9x-8)=81x^2-64

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Solution for (9x+8)(9x-8)=81x^2-64 equation: 


Simplifying
(9x + 8)(9x + -8) = 81x2 + -64

Reorder the terms:
(8 + 9x)(9x + -8) = 81x2 + -64

Reorder the terms:
(8 + 9x)(-8 + 9x) = 81x2 + -64

Multiply (8 + 9x) * (-8 + 9x)
(8(-8 + 9x) + 9x * (-8 + 9x)) = 81x2 + -64
((-8 * 8 + 9x * 8) + 9x * (-8 + 9x)) = 81x2 + -64
((-64 + 72x) + 9x * (-8 + 9x)) = 81x2 + -64
(-64 + 72x + (-8 * 9x + 9x * 9x)) = 81x2 + -64
(-64 + 72x + (-72x + 81x2)) = 81x2 + -64

Combine like terms: 72x + -72x = 0
(-64 + 0 + 81x2) = 81x2 + -64
(-64 + 81x2) = 81x2 + -64

Reorder the terms:
-64 + 81x2 = -64 + 81x2

Add '64' to each side of the equation.
-64 + 64 + 81x2 = -64 + 64 + 81x2

Combine like terms: -64 + 64 = 0
0 + 81x2 = -64 + 64 + 81x2
81x2 = -64 + 64 + 81x2

Combine like terms: -64 + 64 = 0
81x2 = 0 + 81x2
81x2 = 81x2

Add '-81x2' to each side of the equation.
81x2 + -81x2 = 81x2 + -81x2

Combine like terms: 81x2 + -81x2 = 0
0 = 81x2 + -81x2

Combine like terms: 81x2 + -81x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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